Serena is making a model of one of the Egyptian pyramids. The square base has sides that are all 4.2 in. Each of the triangular faces has a base of 4.2 in and a height of 3.6 in. How much paper would it take to cover the entire pyramid 63.5 sq in 72.71 sq in 12 sq in 47.88 sq in
First, find the area of each of the two given shapes... Area of the square...\[A=a^2\] Area of a triangle....\[A=\frac{ hb }{ 2 }\] h is height & b is base
Can you solve these, or would you like help?
if you don't mind helping
No problem. Let's do the square first... A = a^2 1.) Plug the given side of the square into the equation. A = 4.2^2 2.) Solve A = 17.64 Now the triangle... A = (bh)/2 1.) Plug the given base and height of the triangle into the equation. A = (4.2 * 3.6)/2 2.) Solve what is in the parenthesis first. A = 15.12 /2 3.) Now divide by two. A = 7.56 4.) Because there are 4 of the same triangle, multiply the area by 4. A = 7.56(4) 30.24
Now that you have your area for the square and for all 4 triangles, add them together to find the total amount of paper needed... 17.64 + 30.24 = 47.88 So it is the last answer '47.88 sq in'.
thank you for your time
No problem. Glad I could help.
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