Question

Calculate the mass of the products produced by the reaction of 7.5 moles of Na and 7.63 moles of H2O.
2Na + 2H2O ----- 2 NaOH + H2

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Answer 1

@Abhisar

Answer 2

can u help me here buddy i will give you medals and i will be your fan

Answer 3

awww..that's sweet...let's see what we got here.

Answer 4

ok

Answer 5

So from the equation we can see that 2 moles of Na reacts with 2 moles of H2O to produce two moles of NaOH and one mole of H2, this means that 1 mole of Na will react with 1 mole of H20 to produce 1 mole of NaOH and 0.5 moles of H2

Answer 6

is that ok ?

Answer 7

how can we can calculate it?

Answer 8

So, 7.5 moles of Na will react with 7.5 moles of H2O to produce 7.5 moles of NaOH and 3.25 moles of H2

Answer 9

Calculate what ?

Answer 10

the mass?

Answer 11

Ok, now for calculating the final mass of the products, we will do as following.

7.5 moles X Molar mass of NaOH + 3.25 moles X molar mass of H2

Answer 12

= 7.5 X 40 + 3.25 X 2
=300+6.5=306.5 g

Answer 13

how did you get the 3.25?

Answer 14

Because, 1 mole of Na reacts with 1 mole of H2O to form 0.5 moles of H2. So 7.5 moles of Na will react with 7.5 moles of H2O to form 3.25 moles of H2

Answer 15

See the equation
2Na + 2H2O ----- 2 NaOH + H2

Answer 16

how about the 2 NaOH + H2...what is the moles of that?

Answer 17

i need to find the limiting and excess reactant

Answer 18

i dont get it -.-

Answer 19

Yes, you are going correct. Na is limmiting reactant here.

Answer 20

Since, Na is the limmiting reagent, the reaction will be determined by the quantity of Na. So despite the fact that there is 7.63 moles of H2O is present only 7.5 moles of H2O will react with 7.5 moles of Na