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Simplify the expression. -5+i/2i
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\[\Huge\frac{-5+i}{2i}\] ?
Yeah. . .
multiply top and bottom by \(i\)
then use the fact that \(i^2=-1\)
-10i?
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Hey. . .I'm not dun with you. : I
a better way to say that is...I still need more help
people here provide their expertise free of charge
where did you get -10i from
You said multiply top and bottom. . .
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\[\frac{-5+i}{2i}\frac{i}{i}=\frac{-5i+i^2}{2i^2}\]
then use, like I said above, \(i^2=-1\)
How do I do that?
Zaaaaaaaaaaaaaaaaaaaaaaaaaaaaarrrrrrrrrrrrrrrrrraaaaa!
-5(-1)+(-1) 2(-1) ?
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At least complete the task at hand, if you're going to help. >~>
if I do anymore I will just be giving you the answer...and I'm not going to do that.
. . .What a drag.
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