Calculate the mass of the products produced by the reaction of 7.5 moles of Na and 7.63 moles of H2O.
2Na + 2H2O ----- 2 NaOH + H2
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OpenStudy (anonymous):
@thomaster
OpenStudy (anonymous):
@amistre64
OpenStudy (anonymous):
@tkhunny
OpenStudy (anonymous):
@Abhisar
OpenStudy (abhisar):
|dw:1415810789892:dw|
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OpenStudy (anonymous):
ok and?
OpenStudy (abhisar):
The reaction is always driven according to the limmiting reactant. So despite the fact that 7.6 moles of H2O is present, only 7.5 moles of it will react with 7.5 moles of Na
OpenStudy (anonymous):
ok
OpenStudy (abhisar):
and this will produce 7.5 moles of NaOH and 3.25 moles of H2
OpenStudy (anonymous):
so NaOH is 7.5 moles?
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OpenStudy (abhisar):
yes, now you need to calculate the mass of 7.5 moles of NaOH
OpenStudy (abhisar):
It will be 7.5 moles X molar mass of NaOH (which is 40)
OpenStudy (anonymous):
ok
OpenStudy (abhisar):
NOw again find the mass of 3.25 moles of H2. And finally add both the masses to get the final mass of products.
OpenStudy (anonymous):
how about the 2 in NaOH?
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