Question

find a general formula for the nth term

Answer 1

geometric series

Answer 2

a5=1/8 r=1/2

Answer 3

And I am replying you there, and you are here.. Playing hide and seek with me?? :P

Answer 4

lol

Answer 5

this one is different so it confused me

Answer 6

Different?? No..

Answer 7

\[a_5 = \frac{1}{8} \\ ar^{5-1} = \frac{1}{8}\]

Answer 8

What is different here?

Answer 9

\[ar^4 = \frac{1}{8} \\ a(\frac{1}{2})^4 = \frac{1}{8} \\ a(\frac{1^4}{2^4}) = \frac{1}{8}\]

Answer 10

Again \(1^4 = 1\) only.

Answer 11

Hello @rvc how are you??

Answer 12

ok

Answer 13

So, what is different here jessica?

Answer 14

fine
u?

Answer 15

so its 1^4 over 1^1?

Answer 16

Where?

Answer 17

\[1^4 \over 1^1\]

Answer 18

\[a(\frac{1}{2^4}) = \frac{1}{8}\]

Answer 19

ohh

Answer 20

How you got \(1^1\)??

Answer 21

idk T-T

Answer 22

im horrible at math lol

Answer 23

Yeah same is the case with me. :)

Answer 24

So let us multiply by \(2^4\) bot the sides:
\[a = \frac{2^4}{8}\]

Answer 25

ok

Answer 26

thats to 8 also

Answer 27

tell me what is : \(2^3\)?

Answer 28

8

Answer 29

So, 8 can be replaced by \(2^3\), right?

Answer 30

yeah

Answer 31

\[a = \frac{2^4}{2^3}\]

Answer 32

This you will tell me, use the exponent rule, I told you there.

Answer 33

ok

Answer 34

2

Answer 35

Recall:
\[(\frac{x^m}{x^n}) = x^{m-n}\]

Answer 36

Good, it is \(2\)..

Answer 37

ok so its 2(1/2)^n-1?

Answer 38

\[a = \frac{2^4}{2^3} = 2^{4-3} = 2^1 \implies \color{green}{a = 2}\]

Answer 39

Good.. Yes it is.. :)

Answer 40

ok

Answer 41

@rvc I am fine, thanks. :)