Question

Given the function f(x) = x3 + 2x2 - 3x - 5, what is the resulting function when f(x) is shifted to the right 1 unit?

Answer 1

f(x) + 1 = x3 + 2x2 - 3x - 4
f(x) − 1 = x3 + 2x2 - 3x - 6
f(x − 1) = x3- x2 - 4x - 1

Answer 2

f(x) + 1 = x3 + 2x2 - 3x - 4
f(x) - 1 = x3 + 2x2 - 3x - 6
f(x - 1) = x3- x2 - 4x - 1

Answer 3

I think A?
@aaronq @agent0smith @ganeshie8 @iGreen

Answer 4

f(0) = 1 (At x=0 the function is 1). I got this be substituting 0 for all the x's.
So (0,1) is your first point.
At x=1 the function is -4+4-2+1+1 = 0
So (1,0) is your second point.
slope = (0-1) / (1-0) = -1
So the average rate of change for the function between x = 0 and x = 1 is -1

Answer 5

\( f(x) + 1 = x^3 + 2x^2 - 3x - 4\) is the same thing as the original

Answer 6

\( f(x) - 1 = x^3 + 2x^2 - 3x - 6
\) is the same as the original also..only the last option is different.

Answer 7

So the last option would be the correct answer...