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What is the 3rd term of the sequence?
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\[a_{1}=40 \] and \[a _{n}=0.5(a_{n}-1)\]
\[a_{3}=\]
\[\rm a_1 = 40\] and \[a_n = 0.5a_{n-1}\] right ?
which is same as : \[a_n = \frac{1}{2}a_{n-1}\]
plugin n=2 and find the second term first
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which is same as : \[a_2 = \frac{1}{2}a_{2-1} = \frac{1}{2} a_1 = \frac{1}{2}(40) = 20\]
use this to find \(\rm a_3\)
400?
It seems you're taking half of present term to get the next term right ?
\[a_3 = \frac{1}{2}a_{3-1} = \frac{1}{2} a_2 = ?\]
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40?
@ganeshie8
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