Question

IM SERIOUSLY ABOUT TO START CRYING! SOMEONE PLEASE HELP ME IM SO FRUSTRATED!!!!

Answer 1

Log 5^(2x-3)=18

Answer 2

@invinceble @undeadknight26 PLEASE HELP ME!

Answer 3

is this
\[ \log_{10}\left( 5^{2x-3}\right) = 18 \]
or something else ?

Answer 4

yes, that is it, i tried to make it like that but it would not work.

Answer 5

So it is log base 10?
do you know this "rule"
\[ \log(a^b) = b \ \log(a) \]?

Answer 6

no i dont know anything about logs.. Im doing a dba, and i was supposed to get out of school over 30 mins ago... i have 2 questions left..

Answer 7

what is a dba?

Answer 8

Discussion based assessment.

Answer 9

messaging my teach about logs.

Answer 10

logs are confusing but you can survive if you memorize some rules
start with the one just posted
\[ \log(a^b) = b \ \log(a) \]
do you see how to use that rule to re-write your problem?

Answer 11

no.

Answer 12

pattern match
\[ \log_{10}\left( 5^{2x-3}\right) \\ \log_{10}(a^b) \]

Answer 13

the "a" in the rule matches with what ?
and the "b" matches with what (in the problem) ?

Answer 14

a=5
b=^2x-3

Answer 15

b is just the (2x-3) the ^ is just how to show the 2x-3 is an exponent

now use the rule
\[ \log(a^b) = b \ \log(a) \]
what do we get ?

Answer 16

i have no idea...

Answer 17

the rule says if you have a^b inside a log, you can "move the b" outside the law and multiply.

Answer 18

Use
a=5 b=2x-3
and write b log(a) using those expressions for a and b

Answer 19

so... UGH im still confused. -.-

Answer 20

You are learning how to use the rule
\[ \log(a^b) = b \log(a) \]
(learning why it works is possible, but I am guessing you don't want to learn that)
to use the rule you match your problem with the left side
you did that. you found a=5 and b= (2x-3)

now use the right side. write b log(a) but use 5 for a, and 2x-3 for b
can you try ?

Answer 21

I dont have time...

Answer 22

i have to go now.. >.< my teacher is calling me... :/ Thank you anyways.

Answer 23

ok, next time ask before the dba