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Differentiate the function f(x) = xlnx-x
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Is it the product rule?
\[f'(x)= x \frac{ 1 }{ x } + \ln(x) + 1 -1\]
then \[\frac{ x }{ x } + \ln(x) + 1 -1\]
\[f'(x) = 1 + \ln(x) *1 -1\]
so \[f'(x) = lnx\] ?
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Right answer, wrong process for first and second step, I'm sure you mean \(\ln(x)\cdot1\), not \(\ln(x)+1\)
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