polynomial identities help! will medal
You have been hired as an efficiency expert for Math Nerds Inc. The company wants to cut costs and increase profits by increasing the number of math problems their employees can solve in a day. Your job is to help the Math Nerds employees solve math problems more quickly.
Show the Math Nerds employees how to rework each problem below using a polynomial identity. Time yourself working the problem the long way. Then time your self working the problem using a polynomial identity. Show the Math Nerds employees how much time you save on each problem by using the polynomial identity to simplify.
1) ( x+2 )^2 or (x+2) ^2 = (x+y) ^2 = x ^2 +2xy+ y^ 2 2) ( x−3 )^3 or (x−3)^3 = (x−y) ^3 = x ^3 −3 x^ 2 y+3x y^ 2 − y^ 3
@satellite73
can you help me? its part of a project an my teacher is frustrated with me because i dont understand it lol
which defeats the purpose of being a teacher lol
me neither but we can try
i think the idea is this this is an identity \[ (x+y) ^2 = x ^2 +2xy+ y^ 2\]
ok i tried solving it and she said no pluging in triples just work it out like it is. and im like >_< what
ok
so instead of computing \[(x+2)^2\] by writing \[(x+2)^2=(x+2)(x+2)=x^2+2x+2x+4=x^2+4x+4\] you can just say it looks like \[(x+y)^2\] with \[y=2\] and go right to the answer \[(x+2)^2=x^2+2\times 2x+2^2=x^2+4x+4\]
multiply polynomials! And you NEVER distribute the exponent across addition or subtraction like you did. Think about what an exponent means, then expand it (get rid of it by using the definition!) she said this and something about the FOIL method
wait the last one is the answer to the 2nd part?
lets go slow you are confused, me a little too, but you more so
i will bet that when your teacher wrote this : "And you NEVER distribute the exponent across addition or subtraction like you did" it is because you did something like say \[(x+2)^2=x^2+4\]
well for (x+2)^2 i did x(x+4)+4 lol
actually that will work,
but your final answer should look like \(x^2+4x+4\)
oh for the (x+2)^2?
yes
oh ok
now lets get back to that first problem and figure out exactly what your teacher wants you to say
slowly
ok lol
this is a "polynomial identity" \[(x+y) ^2 = x ^2 +2xy+ y^ 2\]
if you can open that it should be the last page
so in order to find \[(x+2)^2\] without writing \((x+2)(x+2)=x^2+2x+2x+4=x^2+4x+4\) instead say \(y=2\) and use the identity to get \[x^2+2\times 2x+2^2=x^2+4x+4\] quicker that is the answer to the first question
ok
so plug in 2 for y in that formula?
yes, i wrote what you get above
same for the last one
ok
can you open the file?
you have \[(x-3)^3\] and instead of writing \\[(x-3)(x-3)(x-3)\] you use the identity \[(x-y)^3=x^3-3x^2y+3xy^2-y^3\]
where you see an \(x\) put an \(x\) and where you see a \(y\) put a \(3\)
so \[(x+2)^2=x^2+2x2x+2^2=x^2+4x+4 \]
Satellite plz help me when ur done thanks
\[(x+2)^2=x^2+2\times 2x+2^2=x^2+4x+4\]
thats for the (x+2)^2
yes
for (x-3)^3 i got \[(x-3)^3=x^3-3x^23+3x3^3-3^3\]
math is not kind to me lol
yeas that is right! then compute the numbers
i solve that?
\[x^3-9x^2+27x+27\]
oh. -_- lol
so what about the 2nd part on 1.?
where (x+2)^2=(x+y)^2=x^2+2xy+y^2
@satellite73
site is messing up sorry
its ok
look i didn't write this it is stupid and there is no wonder you are confused, because it doesn't make sense that thing you just wrote it nonsense, some idiot wrote this sheet
just write \[(x+2)^2=x^2+4x+4\] and be done with it
ok
well thanks
good luck sorry the work sheet is so bad, but at least we got the right answers
yeah lol
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