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Mathematics 18 Online
OpenStudy (jessicawade):

polynomial identities help! will medal

OpenStudy (jessicawade):

You have been hired as an efficiency expert for Math Nerds Inc. The company wants to cut costs and increase profits by increasing the number of math problems their employees can solve in a day. Your job is to help the Math Nerds employees solve math problems more quickly.

OpenStudy (jessicawade):

Show the Math Nerds employees how to rework each problem below using a polynomial identity. Time yourself working the problem the long way. Then time your self working the problem using a polynomial identity. Show the Math Nerds employees how much time you save on each problem by using the polynomial identity to simplify.

OpenStudy (jessicawade):

1) ( x+2 )^2 or (x+2) ^2 = (x+y) ^2 = x ^2 +2xy+ y^ 2 2) ( x−3 )^3 or (x−3)^3 = (x−y) ^3 = x ^3 −3 x^ 2 y+3x y^ 2 − y^ 3

OpenStudy (jessicawade):

@satellite73

OpenStudy (jessicawade):

can you help me? its part of a project an my teacher is frustrated with me because i dont understand it lol

OpenStudy (jessicawade):

which defeats the purpose of being a teacher lol

OpenStudy (anonymous):

me neither but we can try

OpenStudy (anonymous):

i think the idea is this this is an identity \[ (x+y) ^2 = x ^2 +2xy+ y^ 2\]

OpenStudy (jessicawade):

ok i tried solving it and she said no pluging in triples just work it out like it is. and im like >_< what

OpenStudy (jessicawade):

ok

OpenStudy (anonymous):

so instead of computing \[(x+2)^2\] by writing \[(x+2)^2=(x+2)(x+2)=x^2+2x+2x+4=x^2+4x+4\] you can just say it looks like \[(x+y)^2\] with \[y=2\] and go right to the answer \[(x+2)^2=x^2+2\times 2x+2^2=x^2+4x+4\]

OpenStudy (jessicawade):

multiply polynomials! And you NEVER distribute the exponent across addition or subtraction like you did. Think about what an exponent means, then expand it (get rid of it by using the definition!) she said this and something about the FOIL method

OpenStudy (jessicawade):

wait the last one is the answer to the 2nd part?

OpenStudy (anonymous):

lets go slow you are confused, me a little too, but you more so

OpenStudy (anonymous):

i will bet that when your teacher wrote this : "And you NEVER distribute the exponent across addition or subtraction like you did" it is because you did something like say \[(x+2)^2=x^2+4\]

OpenStudy (jessicawade):

well for (x+2)^2 i did x(x+4)+4 lol

OpenStudy (anonymous):

actually that will work,

OpenStudy (anonymous):

but your final answer should look like \(x^2+4x+4\)

OpenStudy (jessicawade):

oh for the (x+2)^2?

OpenStudy (anonymous):

yes

OpenStudy (jessicawade):

oh ok

OpenStudy (anonymous):

now lets get back to that first problem and figure out exactly what your teacher wants you to say

OpenStudy (anonymous):

slowly

OpenStudy (jessicawade):

ok lol

OpenStudy (anonymous):

this is a "polynomial identity" \[(x+y) ^2 = x ^2 +2xy+ y^ 2\]

OpenStudy (jessicawade):

OpenStudy (jessicawade):

if you can open that it should be the last page

OpenStudy (anonymous):

so in order to find \[(x+2)^2\] without writing \((x+2)(x+2)=x^2+2x+2x+4=x^2+4x+4\) instead say \(y=2\) and use the identity to get \[x^2+2\times 2x+2^2=x^2+4x+4\] quicker that is the answer to the first question

OpenStudy (jessicawade):

ok

OpenStudy (jessicawade):

so plug in 2 for y in that formula?

OpenStudy (anonymous):

yes, i wrote what you get above

OpenStudy (anonymous):

same for the last one

OpenStudy (jessicawade):

ok

OpenStudy (jessicawade):

can you open the file?

OpenStudy (anonymous):

you have \[(x-3)^3\] and instead of writing \\[(x-3)(x-3)(x-3)\] you use the identity \[(x-y)^3=x^3-3x^2y+3xy^2-y^3\]

OpenStudy (anonymous):

where you see an \(x\) put an \(x\) and where you see a \(y\) put a \(3\)

OpenStudy (jessicawade):

so \[(x+2)^2=x^2+2x2x+2^2=x^2+4x+4 \]

OpenStudy (anonymous):

Satellite plz help me when ur done thanks

OpenStudy (anonymous):

\[(x+2)^2=x^2+2\times 2x+2^2=x^2+4x+4\]

OpenStudy (jessicawade):

thats for the (x+2)^2

OpenStudy (anonymous):

yes

OpenStudy (jessicawade):

for (x-3)^3 i got \[(x-3)^3=x^3-3x^23+3x3^3-3^3\]

OpenStudy (jessicawade):

math is not kind to me lol

OpenStudy (anonymous):

yeas that is right! then compute the numbers

OpenStudy (jessicawade):

i solve that?

OpenStudy (anonymous):

\[x^3-9x^2+27x+27\]

OpenStudy (jessicawade):

oh. -_- lol

OpenStudy (jessicawade):

so what about the 2nd part on 1.?

OpenStudy (jessicawade):

where (x+2)^2=(x+y)^2=x^2+2xy+y^2

OpenStudy (jessicawade):

@satellite73

OpenStudy (anonymous):

site is messing up sorry

OpenStudy (jessicawade):

its ok

OpenStudy (anonymous):

look i didn't write this it is stupid and there is no wonder you are confused, because it doesn't make sense that thing you just wrote it nonsense, some idiot wrote this sheet

OpenStudy (anonymous):

just write \[(x+2)^2=x^2+4x+4\] and be done with it

OpenStudy (jessicawade):

ok

OpenStudy (jessicawade):

well thanks

OpenStudy (anonymous):

good luck sorry the work sheet is so bad, but at least we got the right answers

OpenStudy (jessicawade):

yeah lol

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