Question

Choose the correct slope of the line that passes through the points (-4, 8) and (-3, -6).

7
-14
0
14

Answer 1

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -4}}\quad ,&{\color{blue}{ 8}})\quad &({\color{red}{ -3}}\quad ,&{\color{blue}{ -6}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)

Answer 2

???

Answer 3

so.... use the given coordinates to get the slope

Answer 4

-6 - (-4) / -3 - 8 ?

Answer 5

-2 / -12?

Answer 6

hold up

Answer 7

one second

Answer 8

-6 - 8/ -3 - 4

Answer 9

am I on the right track?

-4/ -7?

Answer 10

well... one sec

Answer 11

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -4}}\quad ,&{\color{blue}{ 8}})\quad &({\color{red}{ -3}}\quad ,&{\color{blue}{ -6}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ -6}}-{\color{blue}{ (-8)}}}{{\color{red}{ -3}}-{\color{red}{ (-4)}}}\implies \cfrac{-6+8}{-3+4}\implies \cfrac{2}{1}\)

Answer 12

hmm wait a sec... I used -8..

Answer 13

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ -4}}\quad ,&{\color{blue}{ 8}})\quad &({\color{red}{ -3}}\quad ,&{\color{blue}{ -6}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ -6}}-{\color{blue}{ (8)}}}{{\color{red}{ -3}}-{\color{red}{ (-4)}}}\implies \cfrac{-6-8}{-3+4}\implies \cfrac{-14}{1}\)

Answer 14

ooohhhh

Answer 15

I see

Answer 16

I know where I went wrong

Answer 17

- * - = *

Answer 18

hmm - * - = +

Answer 19

so would -14 be correct?

Answer 20

yeap -14/1 = -14

Answer 21

any number is "any number"/1, the same

Answer 22

could you help with 1 more?

Answer 23

sure...you can always post anew.. thus if I dunno.... someone else may
and we can revise each other

Answer 24

Alright, follow me to this thread