Hi! Here's my problem, I'm trying to find factors of polynomials given one of their factors. Here's the example: x^4 + 2x^2 - 8x - 16, x + 2
@ertdre Help please?
to find the other factor of this polynomial, do (x^4+2x^2-8x-16)/x+2
you are trying to find what times x+2 gives you x^4+2x^2-8x-16
Tell me what you get, ask me if you have questions
Okay. I'll be back in a second.
Yup, still confused. I synthetically divided with -2 and got x^3 -8 Where do I go from here?
did you ever learn how to do polynomial division?
Algebra Two w/ Trig is the course I'm taking right now...
im a freshman taking bc calc, but did you ever learn how to divide a polynomia, by another equation?
example: x^2-4 divided by x+2
Oh, I know how to divide synthetically and how to divide long. What I don't know how to do is how to find factors through dividing, even with given a factor.
so basically, a factor is only one half. A factor needs to be multiplied by another factor to reach the end product. Since we are given the end product, we must divide it by the factor that we are given to find the other factor.
sorry if that made no sense
perhaps an example will help
say we are given the number 30, and that 5 is one of its factors
we need to find another factor
since 5*some number= 30, we can say 5x=30
then divide both sides by 5, which gives us x=6 as another factor
it is the same with this problem
x+2 * some number = x^4+2x^2-8x-16
so we divide both sides by x+2 to find the "some number"
some number= (x^4+2x^2-8x-16)/(x+2)
then since you know polynomial division, do x^4+2x^2-8x-16 divided by x+2 to find your answer
But I already did. That's how I got x^3 - 8, and I want to know how to find more factors.
how did you get x^3-8? That doesn't seem right
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