Question

Please Help!

Calculate the following quantity:

Molarity of sodium ion in a solution made by mixing 3.58 mL of 0.348 M sodium chloride with 500. mL of 6.81 x 10^-2 M sodium sulfate (assume volumes are additive)

Answer 1

first write the formulas, this will tell you how many sodium ions are present per mole.

find moles of sodium by using the molarity formula: \(M=\dfrac{n_{solute}}{L_{solution}}\)

add the moles together then divide by the TOTAL volume

Answer 2

Ok thanks :)

Answer 3

np!