Question

Find the derivative of y=cos(2/x).

I know the answer I just need to know the process.

Answer 1

Chain rule: \(\dfrac{d}{dx}f(g(x)) = f'(g(x))g'(x)\)

So \(\dfrac{d}{dx}\cos(2/x) = -\sin(2/x)\cdot-2/x^2 = \boxed{\dfrac{2\sin(2/x)}{x^2}}\)

Answer 2

How did you find the derivative of \[\frac{ 2 }{ x }\]

Answer 3

\(\dfrac{2}{x}=2x^{-1}\)

Use power rule here.

Answer 4

Thank you. Sometimes I overthink things and it really effects my understanding of calculus.

Answer 5

No problem