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Calculus1 8 Online
OpenStudy (anonymous):

Differentiate. f(t)= square root of (lnt+t)

OpenStudy (anonymous):

@Leader can you help? lol sorry for keep tagging you

OpenStudy (leader):

Sorry don't know this...

OpenStudy (tkhunny):

Is it \(\sqrt{\ln(t) + t}\)?

OpenStudy (anonymous):

Yea, differentiate it ^

OpenStudy (tkhunny):

Do these: \(f(x) = \sqrt{x}\) \(g(x) = \ln(x)\) \(h(x) = x\) Find \(f'(x),\;g'(x),\;and\;h'(x)\)

OpenStudy (anonymous):

\[\frac{ t+1 }{ 2t \sqrt{\ln t +t}}\]

OpenStudy (anonymous):

\[f(t)=\sqrt{\ln(t)+t}\] \[f(t)=(\ln(t)+t)^{1/2}\] \[f'(t)=\frac{ 1 }{ 2 }(\ln(t)+t)^{-1/2}\times(\frac{ 1 }{ t }+1)\] \[f'(t)=\frac{ 1 }{ 2\sqrt{\ln(t)+t} }\times(\frac{ 1 }{ t }+1)\] \[f'(t)=\frac{ 1+t }{ 2t \sqrt{\ln(t)+t} }\]

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