Question

Differentiate. f(t)= square root of (lnt+t)

Answer 1

@Leader can you help? lol sorry for keep tagging you

Answer 2

Sorry don't know this...

Answer 3

Is it \(\sqrt{\ln(t) + t}\)?

Answer 4

Yea, differentiate it ^

Answer 5

Do these:

\(f(x) = \sqrt{x}\)
\(g(x) = \ln(x)\)
\(h(x) = x\)

Find \(f'(x),\;g'(x),\;and\;h'(x)\)

Answer 6

\[\frac{ t+1 }{ 2t \sqrt{\ln t +t}}\]

Answer 7

\[f(t)=\sqrt{\ln(t)+t}\]
\[f(t)=(\ln(t)+t)^{1/2}\]
\[f'(t)=\frac{ 1 }{ 2 }(\ln(t)+t)^{-1/2}\times(\frac{ 1 }{ t }+1)\]
\[f'(t)=\frac{ 1 }{ 2\sqrt{\ln(t)+t} }\times(\frac{ 1 }{ t }+1)\]
\[f'(t)=\frac{ 1+t }{ 2t \sqrt{\ln(t)+t} }\]