Question

Can someone please explain to me what I am doing wrong with this differentiate problem? Equation in comments

Answer 1

\[f(x)=3\sqrt{x}.sinx\]
this is the function right?

Answer 2

yes. My teacher hasn't taught us the chain rule yet

Answer 3

so diffrentiating it \[f'(x)=3[\sqrt{x}.cosx+sinx.\frac{ 1 }{ 2\sqrt{x} }]=3\sqrt{x}.cosx+sinx.\frac{ 1 }{ \frac{ 2 }{ 3} \sqrt{x}}]\]

Answer 4

ok chain rule is not needed here
see your mistake?
it will be 2/3=0.67 not 3/2=1.5

Answer 5

finally\[f'(x)=3\sqrt{x}.cosx+\frac{ sinx }{ 0.67.\sqrt{x} }\]

Answer 6

ohhh okay

Answer 7

:)