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OpenStudy (anonymous):
x = 2
OpenStudy (anonymous):
I don't know, I'm probably wrong.
OpenStudy (anonymous):
x^2 - 6x - 7 = 0
(x-7)(x+1)
So x = 7; x = -1
Check your work:
7^2 - (6)(7) - 7 = 0
49 - 42 - 7 = 0
0 =0
(-1)^2 - (6)(-1) - 7
1 + 6 - 7 = 0
0 = 0
So, they check.
OpenStudy (anonymous):
@biggdaddymiller That answer is wrong
OpenStudy (anonymous):
x = -2
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OpenStudy (anonymous):
lol
OpenStudy (anonymous):
@biggdaddymiller I still think that is wrong :( I'm pretty sure I solved it correctly
OpenStudy (anonymous):
yea iz 0=0 me chacked :)
OpenStudy (anonymous):
@KILL4PHUN So I'm right
OpenStudy (anonymous):
yupp.
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OpenStudy (anonymous):
@mdf913 My answer is correct :) Happy to help
OpenStudy (anonymous):
A) x=-1 x= -5
B) 3 (plus/minus) square root of 2
C) -3 (plus/minus) square root of 2
D) -3 + Square root of 2 divided by 2
OpenStudy (anonymous):
These are my answer choices @lauren24680
OpenStudy (anonymous):
\[\times\]
OpenStudy (anonymous):
Okay, I'm pretty sure the answer is A
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OpenStudy (anonymous):
Thank you so much!! :)
OpenStudy (anonymous):
You're welcome! :)
OpenStudy (anonymous):
I have more if you want to help more. If you don't mind. ._.
OpenStudy (anonymous):
Alright, I'll try it :)
OpenStudy (anonymous):
Which of the following is a solution of x2 + 5x = -2?
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OpenStudy (anonymous):
\[5\pm (\square \root) of 33 divided by 2\]
OpenStudy (anonymous):
B) 5 (plus/minus) square root of 17 divided by 2
C) -5 (plus/minus) square root of 33 divided by 2
D) -5 (plus/minus) the square root of 17 divided by 2