Mathematics
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OpenStudy (anonymous):
Calculate the flux of the vector field F = 3i + 6j through a square of side 4 lying in the plane x + y + z = 15 oriented away from the origin.
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OpenStudy (sidsiddhartha):
\[flux=F.A\]
so first try to find out the area vector
OpenStudy (sidsiddhartha):
so i can say that the an upward normal vector is\[A_u=\hat{i}+\hat{j}+\hat{k}\]
OpenStudy (sidsiddhartha):
so the unit normal vector will be
\[A_{UN}=\frac{ \hat{i}+\hat{j}+\hat{k} }{ \sqrt{1^2+1^2+1^2} }=\frac{ \hat{i}+\hat{j}+\hat{k} }{ \sqrt{3} }\]
OpenStudy (sidsiddhartha):
ok?
OpenStudy (sidsiddhartha):
so the area vector will be\[A_v=A_{UN}*4=\frac{ 4(\hat{i}+\hat{j}+\hat{k}) }{ \sqrt{3} }\]
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OpenStudy (sidsiddhartha):
so \[flux=F.A_v\]
OpenStudy (sidsiddhartha):
so do a little dot product
OpenStudy (anonymous):
what would i do with the =15?
OpenStudy (sidsiddhartha):
\[flux=(3 \hat{i}+4 \hat{j})*\frac{ 4(\hat{i}+\hat{j}+\hat{k}) }{ \sqrt{3}}\]
OpenStudy (sidsiddhartha):
15 is just a constant
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OpenStudy (anonymous):
so just (12+16+4)/square root(3)
OpenStudy (sidsiddhartha):
why 12+16+14
OpenStudy (anonymous):
so 32/square root(3)
OpenStudy (anonymous):
wait just (12+16)/square root(3)
OpenStudy (sidsiddhartha):
\[Flux=\frac{ 4 }{ \sqrt{3} }*(\hat{i}+\hat{j}+\hat{k})(3 \hat{i}+4\hat{j})=\frac{ 4 }{ \sqrt{3} }*(3+4)=\frac{ 28 }{ \sqrt{3} }\]
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OpenStudy (sidsiddhartha):
yes that should be it !!
OpenStudy (sidsiddhartha):
matches your answer?
OpenStudy (anonymous):
got it thanks
OpenStudy (anonymous):
:)
OpenStudy (sidsiddhartha):
yw!!
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OpenStudy (anonymous):
wait
OpenStudy (anonymous):
we did it wrong
OpenStudy (anonymous):
it should be (3i+6j) * 4/square root(3) (i+j+k) right?
OpenStudy (anonymous):
@sidsiddhartha
OpenStudy (sidsiddhartha):
oohh my bad sorry
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OpenStudy (sidsiddhartha):
then\[36/\sqrt{3}\]
right?
OpenStudy (anonymous):
yeah but its making it wrong :(
OpenStudy (anonymous):
marking it wrong
OpenStudy (anonymous):
what are we doing wrong?
OpenStudy (sidsiddhartha):
i dont know @perl can u check this out?
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OpenStudy (sidsiddhartha):
ok u can put a minus ahead of the answer and check it again but not sure it will work or not
OpenStudy (anonymous):
no it didnt work
OpenStudy (sidsiddhartha):
as the vector is oriented away from the origin
OpenStudy (anonymous):
it also marking wrong -36/square root(3)
OpenStudy (sidsiddhartha):
try \[12\sqrt{3}\]
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OpenStudy (anonymous):
does "square of side 4 lying in the plane" has something to do with it?
OpenStudy (anonymous):
no the 12 didnt work
OpenStudy (anonymous):
I only have one more try left
OpenStudy (sidsiddhartha):
ok let me tag experts @Kainui
OpenStudy (sidsiddhartha):
@ganeshie8
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OpenStudy (anonymous):
thanks
OpenStudy (anonymous):
what about (3i+6j)*16(i+j+k)/square root(3)
OpenStudy (anonymous):
because of the square of side 4
OpenStudy (sidsiddhartha):
yes i missed it
OpenStudy (anonymous):
you think so?
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OpenStudy (sidsiddhartha):
yes area=16
OpenStudy (anonymous):
so 144/square root(3)
OpenStudy (sidsiddhartha):
yes it should be okay !!
OpenStudy (anonymous):
NO :( I got it wrong
OpenStudy (anonymous):
so what do you think the answer should be?
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OpenStudy (anonymous):
can you help me with this one
OpenStudy (anonymous):
@sidsiddhartha
OpenStudy (sidsiddhartha):
what were the options for the last one?
OpenStudy (sidsiddhartha):
@SithsAndGiggles
OpenStudy (anonymous):
for the flux? it didn't have options
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OpenStudy (anonymous):
can you help me with the screen shot that i post? please :)
ganeshie8 (ganeshie8):
done with the main question right ?
OpenStudy (sidsiddhartha):
no the answer is'nt correct she says, can u check it @ganeshie8
OpenStudy (anonymous):
it was not the current density. I got it wrong. ;( what should the right answer be? @ganeshie8
OpenStudy (anonymous):
yeah I would like to know what we did wrong
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OpenStudy (sidsiddhartha):
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