To find the inverse:
Replace f(x) with y
Switch x's and y's, so put x where y is and x where y is.
Solve for y
Replace y with f^-1(x)
Follow these steps, and see what you get, and once you have the inverse plug in the 3.
jagr2713 (jagr2713):
@iambatman i dont get it can you do it please?
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OpenStudy (anonymous):
You didn't even try it.
jagr2713 (jagr2713):
i did that before i dont get it
OpenStudy (anonymous):
I'm not going to do this for you, I will help guide you but you need to do the heavy lifting.
OpenStudy (anonymous):
Well can you show me your process?
OpenStudy (anonymous):
I can then pin point where you went wrong.
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Follow the steps I gave you, switch the x's and y's.
jagr2713 (jagr2713):
so x=2y+3/5
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OpenStudy (anonymous):
Yes :)
OpenStudy (anonymous):
Now solve for y
jagr2713 (jagr2713):
then we multiply right?
OpenStudy (anonymous):
Multiply what?
jagr2713 (jagr2713):
5 and 3?
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OpenStudy (anonymous):
Yes you multiply 5 but not 3, write it out, it will make much more sense.
jagr2713 (jagr2713):
so u muliply 5 with x and get 5x=2y+3
jagr2713 (jagr2713):
@iambatman
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
What you do to one side you must do to the other, remember this, so do same stuff on your right side on the left as well. That's algebra.
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jagr2713 (jagr2713):
then we reverse the equality and get 2y+3=5x?
OpenStudy (anonymous):
It doesn't matter, but that's fine.
OpenStudy (anonymous):
Solve for y, what's your next step/
jagr2713 (jagr2713):
then isolate and get 2y=5x-3
then solve for y >?
jagr2713 (jagr2713):
so its
y=5x/2 - 3/2
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OpenStudy (anonymous):
Yes that's good
jagr2713 (jagr2713):
So i am done?
OpenStudy (anonymous):
\[f^{-1}(x) = \frac{ 5x-3 }{ 2 }\] now quite, now plug in 3 for x and that will give you\[f^{-1}(3)\]
jagr2713 (jagr2713):
5(3)-3/2
15-3/2
12/2
6
OpenStudy (anonymous):
Yup :)
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OpenStudy (anonymous):
Good job!
jagr2713 (jagr2713):
so am done :D thxxxx
OpenStudy (anonymous):
Yes, now you're done
jagr2713 (jagr2713):
wait i got 6 for all of them
OpenStudy (anonymous):
What do you mean?
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jagr2713 (jagr2713):
Which of the following statements have the same result? Explain each step in solving each one.
f(1) when f(x) = 5x + 1
f-1(3) when f(x) = 2x plus 3, all over 5
3y - 7 = y + 5
jagr2713 (jagr2713):
i got 6 for all 3
OpenStudy (anonymous):
That's fine
OpenStudy (anonymous):
Explain your reasoning for all of them then :)
jagr2713 (jagr2713):
oh ok thx
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jagr2713 (jagr2713):
wait you want to explain it now
OpenStudy (anonymous):
Just to make sure we did the right problem, your question was \[f(x) = \frac{ 2x+3 }{ 5 }\] and not \[f(x) = 2x+\frac{ 3 }{ 5 }\]