Question

y = 7/5x- 0

Answer 1

y intercept is what you get when you replace x by 0, namely \(-6\)

Answer 2

x intercepts is what you get when you solve
\[\frac{1}{2}x^2-x-6=0\]

Answer 3

probably easier to do this by multiplying by 2 first and solving \\[x^2-2x-12=0\]

Answer 4

fortunately this one factors, so it will not be too hard to solve

Answer 5

wait so @satellite73 what do I do?

Answer 6

how do I do it?

Answer 7

we can either use the quadratic formula, or complete the square
which would you prefer?

Answer 8

completing the square is easiest

Answer 9

you know how to do that or you want me to walk you through it?

Answer 10

ok here we go
\[x^2-2x-12=0\] add \(12\) and get '
\[x^2-2x=12\] then take half of 2, which is one, and complete the square via
\[(x-1)^2=12+1=13\] this makes
\[x-1=\pm\sqrt{13}\] and so the two intercepts are
\[x=1+\sqrt{13}\] and \[x=1-\sqrt{13}\]

Answer 11

yw