Question

how do i simplify 27d/ 27d^2+18d

Answer 1

Is this it:
\[\frac{27d}{27d^2}+18d\]
?

Answer 2

If it is, firstly, eliminate \(27d\) from the numerator and denominator
\[\frac{27d}{27d^2}+18d\]
\[(\frac{27d}{27d^2})/27d+18d\]
\[\frac{1}{d}+18d\]
\[\frac{1}{d}+\frac{18d}{1}\]
Multiply the \(\frac{18d}{1}\) by \(d\) to get a common denominator
\[\frac{1}{d}+(\frac{18d}{1})*\frac{d}{d}\]
\[\frac{1}{d}+\frac{18d^2}{d}\]
\[\frac{18d^2+1}{d}\]

Answer 3

no it was what i had, but i was looking at it again and i think i got it. thanks any way. @Ahsome

Answer 4

No problem @Manuela100 :)