Question

Hiiiii has to do with solving systems by substitution.

Answer 1

sorry gurl i have no idea! XC

Answer 2

isolate y in the 2nd equation

Answer 3

Your two equations:
\[-4.5x-2y=-12.5\]\[3.25x-y=-0.75\]

In the second equation, try to get \(y\) by itself
\[3.25x-y=-0.75\]\[-y=-0.75-3.25x\]\[y=-1(-0.75-3.25x)\]\[y=0.75+3.25x\]

Substitute that \(y\) value into the first equatio
\[-4.5x-2y=-12.5\]
Sub the \(y\) value found before
\[-4.5x-1.5-6.5x=-12.5\]
Simplify
\[-11x-1.5=-12.5\]
\[-11x=11\]
\[x=\frac{11}{-11}\]
\[x=-1\]

Now substitute the \(x\) value into the equation to find \(y\)
\[y=0.75+3.25x\]\[y=0.75+3.25*-1\]\[y=0.75-3.25\]\[y=-2.5\]

Answer 4

!!!!! ok i surrendur

Answer 5

Hope that helps, @Happipily

Answer 6

@Ahsome It really does thank you so much!

Answer 7

No problem @Happpily :D