WILL GIVE MEDAL
Let \(x\) be the number of boys Let \(y\) be the number of girls Boys and girls equals 89 \(x+y=89\) Boys = girls + 8 \[x=y+8\]
Does that make sense, @VJT?
yeah
so what choice is it
ok
\[x+y=89\]\[x=y+8\] Now you know that \(x=y+8\), we can put that into the first question \[x+y=89\] Sub in \(x\) \[(y+8)+y=89\]\[2y+8=89\]\[2y=89-8\]\[2y=81\]\[y=\frac{81}{2}\]\[y=40.5\] Now we know \(y\), we can sub that into the equation to get \(x\) \[x=y+8\] Sub in \(y\) \[x=40.5+8\]\[x=48.5\]
Does that make sense, @VJT?
yes
Thats the answer
Whoops. Did something wrong
ok, i was going to say that, that wasn't a choice
\[x+y=89\]\[x=2y+8\] Now you know that \(x=2y+8\), we can put that into the first question \[x+y=89\] Sub in x \[(2y+8)+y=89\]\[3y+8=89\]\[3y=89−8\]\[3y=81\]\[y=\frac{81}{3}\]\[y=27\] Now we know y, we can sub that into the equation to get x \[x=2y+8\] Sub in y \[x=2*27+8\]\[x=2*27\]\[x=54\] Therefore, the number of boys is \(54\)
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