Question

what is a polynomial function in standard form with zeros 1,2,-2, and -3

Answer 1

ax^4+bx^3+cx^2+dx+e
is this what are you asking for

Answer 2

i guess so.

Answer 3

\[ax^4+bx^3+cx^2+dx+e\]

Answer 4

but i dont have abcde, how do i find them

Answer 5

a,b,c,and d =1 and e=0

Answer 6

x^4+x^3+x^2+x

Answer 7

general form is
a*(x-r_1)(x-r_2)...(x-r_n), where r_1, r_2, ... r_n are roots

Answer 8

we can choose a = 1 , or any number you want (except zero), 1 is simplest
f(x) = 1* ( x - 1) ( x - 2) ( x - (-2) ) ( x - (-3) )

Answer 9

now your job is to simplify that, and expand it

Answer 10

these are my choices.
x^4 + 2x^3 +7x^2 -8x + 12
x^4 + 2x^3 -7x^2 -8x + 12
x^4 - 2x^3 +7x^2 +8x + 12
x^4 + 2x^3 +7x^2 +8x + 12

Answer 11

of course you could copy and paste it into wolfram

Answer 12

im not allowed to give answer :/

Answer 13

i tried wolfram. it gave me decimals like 1.0006783

Answer 14

http://www.wolframalpha.com/input/?i=expand+%28+x+-+1%29+%28+x+-+2%29+%28+x+-+%28-2%29+%29+%28+x+-+%28-3%29+%29+

Answer 15

i understand you cant give an answer but i dont understand how abcd =1 and e=0 then it gets to the others.

Answer 16

where are you getting abcd = 1

Answer 17

may I see what you put into maple, how you got 1.0006783

Answer 18

the polynomial is given by (x-1)(x-2)(x+2)(x+3)={(x-1)(x+3)}{(x-2)(x+2)}
=(x^2+2x-3)(x^2-4).
Rest you may compute?.@minimoo

Answer 19

@minimoo