Confirmation from polar to Cartesian

Question

ahsome · Answer

I have a point, $(10, 30)$ in polar co-ordinate form. I want to turn into cartesian. Is this the right working?
$$x=r*cos\theta$$$$x=10*cos(30)$$$$x=8.66$$
$$y=r*sin\theta$$$$y=10*sin(30)$$$$y=5$$
$$\begin{bmatrix}
x \
y
\end{bmatrix}$$
Sub in values:
$$\begin{bmatrix}
8.66 \
5
\end{bmatrix}$$

fibonaccichick666 · Answer

If you are given it in the form (r,$\theta$), it appears correct(Idid not check calculations) Although, I cannot remember if it is necessary to make it a vector or not

ahsome · Answer

We do use it in vectors, since then we can find end displacement.

fibonaccichick666 · Answer

when you switch back, if it was not one to begin with, but I also do not recall ever seeing polar as anything but a vector, so I believe it is correct

ahsome · Answer

I believe that is the reason

ahsome · Answer

Thank you @FibonacciChick666

fibonaccichick666 · Answer

Np, it's been like 4 years since calc III for me, so if you happen to have any extremely difficult integral problems, or problems in general. please tag me so I can work on them.  (I'm studying for the GRE)

ahsome · Answer

Sure, thanks again @FibonacciChick666 :D

ahsome · Answer

(This questions also gives me a reason to try $\LaTeX$ Matrix :D

fibonaccichick666 · Answer

:) NIce!