Question

tan90+45

Answer 1

What are you trying to find?

Answer 2

Is it
Tan(90+45)?

Answer 3

We need more info

Answer 4

\[tan(90)\] IS undefined

Answer 5

tan90+teta

Answer 6

Umm...
\[tan(90)+\theta\]?

Answer 7

Bracket?

Answer 8

\[tan(90+45)\]?

Answer 9

tan135

Answer 10

Ok. Thats easy
\[tan(135)\]\[=-1\]

Answer 11

how

Answer 12

Tan(90+45)=-cot45

Answer 13

How it does that is really complicated, @madgularahul. I think inputting into a calculator should be fine

Answer 14

no its -1

Answer 15

What hemans is:
\[tan(135)=-cos(45)\]\[-cos(45)=-1\]

Answer 16

Cot45=1

Answer 17

He wants to know how \(tan(135)\) is \(-1\)

Answer 18

Yes, first start with a drawing to understand which quadrant angle 135 is in.

Answer 19

You know that in quadrant 1, \(\tan(45) = 1\) therefore, tangent is negative in quadrant 2, where we have the angle 135. I think this is what is called a complementary angle.

Once you know what the original angle in quadrant 1 is, finding other angles is simple.

Answer 20

Here is a way to see it:

Answer 21

\(\text{All Students Talk Crap}\)
Quote by my Maths Teacher

Answer 22

To be more precise, \(\tan(45 + 90) = \tan(135)\) and so finding what \(\tan(45)\) is, all you need to find now is whether your answer is positive or negative. \[\tan(135) =\frac{y}{x} = \frac{\sqrt{2}}{2} \cdot -\frac{2}{\sqrt{2}} = -1\]

Answer 23

Do you understand? :)

Answer 24

Maybe I should have written i as : \[\tan(135) =\frac{3\pi}{4} \]At 3pi/4, we have \(x= -\frac{\sqrt{2}}{2}\) and \(y= \frac{\sqrt{2}}{2}\) \[\tan(\theta)= \frac{y}{x} \implies \frac{\sqrt{2}}{2} \cdot -\frac{2}{\sqrt{2}} = -1\]

Answer 25

good mnemonic