Question

Limit

Answer 1

\[\lim_{n \rightarrow \infty}\sqrt{n^2+2n+3}-n\]

Answer 2

@ganeshie8 @campbell_st

Answer 3

@Abhisar @dan815 @e.mccormick @waterineyes

Answer 4

rainbowgirl it's a limit (You look like you've never heard of calculus)

Answer 5

You want to find a way to eliminate the square root . this function is \[\lim_{x \rightarrow \infty} \frac{n-\sqrt{n^2+2n+3}}{1}\]In cases like these, you multiply by the conjugate, \( n+ \sqrt{n^2 +2n +3}\)

Answer 6

@Jhannybean thx

Answer 7

you multiply both top and bottom of your original function by the conjugate* sorry.

Answer 8

Similar to \( (a-b)(a+b) = a^2 -b^2\), you will by left with a square root-less function ontoop, with your conjugate on bottom. Do you still need me to explain further? :)

Answer 9

@Jhannybean I got the idea

Answer 10

Great :) good luck!