Calculus 3: Set up limits of the integral \[\int \int \int f(x,y,z)dzdxdy\]with vertices \((0,0,0),(2,0,0), (2,1,0)\) and \((2,1,1)\)
Calculus is the mathematical study of change, in the same way that geometry is the study of shape and algebra is the study of operations and their application to solving equations.
Lol, im editting my question, one minute
The only part I am confused with is finding the limits of z. I know the base is \(z =0\) but finding the upper limit of z is confusing me just a little bit.
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So i know the projection, or even the function in the xy-plane looks like |dw:1415993974643:dw|
the easiest domains to integrate over are straight lines (for integrals) , rectangular regions (for double integrals) and rectangular box regions (for triple integrals)
so here we dont have a rectangular box, so we need to do some work
Yeah, using slopes and such.
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