0.19494949494.....in a fraction???
It might be easier to write 1.9494949494... As a fraction. 1 + 94/99 = (99+94)/99 = 193/99 Done Okay, now how do we answer the question?
you can multiply this by the period
Example: This is my favorite way: Say we wanted to write .331331331331331... as a fraction. \[\text{ Let } x= .331331331... \\ \text{ so } 1000x=331.331331... \\ 1000x-x=331.331331...-.331331331 \\ 999x=331 \\ x=\frac{331}{999} \\ \]
@perl are you saying 194/99?right
not exactly
i dont think you have to find the exact rational number the question says, is this a rational number It is a mathematical fact that repeating decimals are rational numbers.
eventually repeating decimals*
mathematical fact = theorem (which means we can prove it)
I'll just finish teh argument if x = 0.19494949494.... then 10x = 1.949494... 1000x = 194.949494... 1000x - 10x = 193 990x = 193 x = 193/990
ok i see my mistake earlier, there is a nice algorithm .19494949 = .1 + .0949494.... = 1/10 + 94/990
so if you have an eventually repeating decimal cut out the part which is not repeating and add it the repeating decimal.
lets do another example consider the decimal .13678678678... we see that '678' repeats .13678678678... = .13 + .00678678... = 13/100 + 678/99900
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