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Question

gokuporter · Answer

@BPDlkeme234

gokuporter · Answer

@UnkleRhaukus

unklerhaukus · Answer

$$2\tfrac13+3\tfrac43\=2+\tfrac13+3+\tfrac43\
=2+3+\tfrac13+\tfrac43\=2+3+(\tfrac13+\tfrac43)\=2+[3+(\tfrac13+\tfrac43)]\=$$

unklerhaukus · Answer

simplify the terms in the parentheses, and then simplify the terms in the brackets

gokuporter · Answer

D? @UnkleRhaukus

anonymous · Answer

starting inside parenthesis:as @UnkleRhaukus advises yields:
1/3 + 4/3 = 5/3
2+ 3(5/3) = 2 + 5 = 7
which is not an option

unklerhaukus · Answer

Whoops, i made a mistake

$$2\tfrac13+3\tfrac34\=2+\tfrac13+3+\tfrac34\
=2+3+\tfrac13+\tfrac34\=2+3+(\tfrac13+\tfrac34)\=2+[3+(\tfrac13+\tfrac34)]\=$$

unklerhaukus · Answer

hmm, none of the options are enough honey

unklerhaukus · Answer

maybe they expect you to make approximations early
$$2\tfrac13\sim 2\tfrac12$$
$$3\tfrac34\sim4$$

anonymous · Answer

Take two:
2and1/3 + 3and3/4
Ah I see what you are doing @UnkleRhaukus: separating out fractions
2+1/3 + 3 + 3/4
using associative property of addition
2 + 3 + 1/3 + 3/4
2+3+ 4/12  + 9/12
2+3+13/12
yes I got same - none of answers suit