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evaluate w/o calculator: ln e
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i have 1 for an answer, is this correct?
Yes, that would be correct. :-)
how can i show work. i just seen it was a natural log
\[\ln e=\log_ee^1=1\log_ee=1\]
Suppose that \(\ln e = x\). Recalling that \(\ln a = \log_e a\), this equation is the same as considering \(\log_e e = x\). In exponential form, this is equivalent to saying \(e^x=e\). Since \(e=e^1\), this is now equivalent to \(e^x=e^1\) and since they have the same base, their exponents must be the same. Hence \(x=1\) and therefore \(\ln e = 1\).
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is unklerhaukus explanation correct?
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