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Mathematics 20 Online
OpenStudy (anonymous):

find the derivative

OpenStudy (anonymous):

OpenStudy (alyssa_xo):

Use the product rule. \(\frac{d}{dx}f(x)g(x)=f'(x)*g(x)+f(x)g'(x)\)

OpenStudy (alyssa_xo):

or u'v + uv'

OpenStudy (anonymous):

does e^x stay the same?

OpenStudy (anonymous):

yes the derivative of e^x=e^x

OpenStudy (anonymous):

is the f' the (5x^2+3x+2) ? and the g(x) is e^x?

OpenStudy (alyssa_xo):

f' is the derivative of that thing

OpenStudy (anonymous):

(10x+3)e^x+e^x(5x^2+3x+2)

OpenStudy (anonymous):

is that it im not sure?

OpenStudy (alyssa_xo):

that looks right

OpenStudy (alyssa_xo):

I prefer having the visual of u'v + uv' so I'd write it out as \((10x+3)e^x+(5x^2+3x+2)e^2\)

OpenStudy (anonymous):

oh yea me too i just dont know how to write the equations on here lol i haven't gotten used to it

OpenStudy (alyssa_xo):

there's a button or you can use ``` \(equation\) \[equation\] ```

OpenStudy (anonymous):

oh thanks i think i have to play around with it to get used to it

OpenStudy (alyssa_xo):

mhm

OpenStudy (anonymous):

thank you :) i got it

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