cos 5x ��������� cos 7x = 0 @perl
Θ
cos A - cos B = -2 Sin (A+B)/2. Sin (A-B)/2
cos(5x) - cos(7x) = 0 ?
yes @perl sorry
you can use this formula to simplify: cos A - cos B = -2 Sin (A+B)/2. Sin (A-B)/2 where A = 5x and B= 7x
cos(5x) = cos(7x)
take inverse cosine of both sides
midhun, how does that substitution make it easier to solve for x ? (exactly)
i dont really know thats why i posted my question
what are the directions, solve for x ? in degrees or radians
Taking inverse I am not sure about it.. so I chose this method...
@perl can u please check this link? http://openstudy.com/study#/updates/5466d220e4b05b0e1f1daae8
oh i see
then you used zero product property
But I dont know whether this can be done in a simpler way taking inverse as you said
yess
right, we can take invercosine of both sides
can u just do that for me
sure
btw @kimberlyevens... you understood that method?
cos(5x) = cos(7x) 5x = 7x + 2pi*n 5x = -7x + 2pi*n
|dw:1416026935751:dw| what would be the next step?
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