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Mathematics 9 Online
OpenStudy (anonymous):

use reference angles to find exact value of the expression. sin -2pi/3

OpenStudy (jhannybean):

Think about the unit circle |dw:1416049753174:dw|

OpenStudy (jhannybean):

What is the angle measure here?

Miracrown (miracrown):

Are you familiar with the ordered pairs on the unit circle ? @dabeezy

Miracrown (miracrown):

-2pi/3 has the same coterminal angle as 4pi/3 So, what is the ordered pair at that angle location?

OpenStudy (jhannybean):

|dw:1416050039102:dw| if in quadrant 1, sin is \(\frac{\sqrt{3}}{2}\) , then you have to ask yourself what the supplementary angle to \(\frac{\pi}{3}\)would give you a negative value of \(\frac{-\sqrt{3}}{2}\)

OpenStudy (anonymous):

sorry guys i was on a web site, im here now. i have this worked out. im going to submit my answer. check my work please

OpenStudy (jhannybean):

Sure, as long as you're posting it here we can :)

OpenStudy (anonymous):

i am, just takes a min. have to use phone

OpenStudy (anonymous):

OpenStudy (anonymous):

@Jhannybean

OpenStudy (jhannybean):

You have really nice writing, I must say.

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

is work correct?

OpenStudy (jhannybean):

I would have done it like this.

Miracrown (miracrown):

The hand writing is even better than mine! :O

OpenStudy (anonymous):

OpenStudy (anonymous):

i drew that from this

OpenStudy (jhannybean):

|dw:1416051731904:dw|\[\ 240 \cdot \frac{\pi}{180} = \frac{4\pi}{3}\]\[\sin\left(\frac{4\pi}{3}\right) = -\frac{\sqrt{3}}{2}\]

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