Indefinite Integrals related problem: The acceleration due to gravity on Mars is approximately 3.72 m/sec2. If an astronaut jumps straight up on the surface of the planet with an initial velocity of 2 m/sec, what height will she attain? Find the comparable height that she would jump on the earth.

Question

jhannybean · Answer

Can you use physics to solve this?

miracrown · Answer

Perhaps

jhannybean · Answer

$$V_{f_y}^2 = V_{i_y}^2 + 2a_{y}\Delta y$$

anonymous · Answer

No. I've to use calculus.

miracrown · Answer

We are given the acceleration due to gravity on Mars, which is approximately (3.72 m per second) per second. 	This is a constant, acceleration function.

miracrown · Answer

Do you know how to find a velocity function on Mars ? @Erroneous_Copper

jhannybean · Answer

Oh, then possibly $$\int a(t)dt =v(t) +c \implies \int (v(t) +c)dt=s(t) +ct +d$$ something like that perhaps.

jhannybean · Answer

and s(t) would be the position function (or height) at a given time.

miracrown · Answer

v(t) , yes :)
next, what is the antiderivative of 3.72 dt ?

miracrown · Answer

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