Question

Need help with factoring quadratics, will medal.

Factor completely 81x2– 100

Answer 1

\[\large \bf 81x^2-100\]
you can write it as also :-
\[\large \bf 81x^2-10^2\]

Answer 2

Use
\[\large \bf a^2-b^2=(a-b)(a+b)\]

Answer 3

and then solve

Answer 4

hope you understand. @AskingAlex_cx

Answer 5

So plug in for a^2 - b^2... 81x^2-10^2 right?

Answer 6

right

Answer 7

can you solve it ? @AskingAlex_cx

Answer 8

Help me understand @mayankdevnani

Answer 9

ok

Answer 10

\[\large \bf 81x^2-10^2\]
Use \[\large \bf a^2-b^2=(a-b)(a+b)\]
we get,
\[\large \bf (9x)^2-(10)^2\]
\[\large \bf (9x-10)(9x+10)\]

Answer 11

there you go !
your problem is SOLVED !

Answer 12

I just didn't know where to take it next, I thought about sqrt the 81, but wouldm't you have to do the same to both sides?

Answer 13

see
81=9*9=9^2

Answer 14

and 100=10*10=10^2

Answer 15

yes, but the 81 is already squared, so square rooting would make it just 9 right?

Answer 16

no
81 is not squared,x is squared.
Notice in your question DEEPLY.
`You have put squared on x not on 81`

Answer 17

ohh thanks a lot!! @mayankdevnani

Answer 18

welcome :)