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Someone help please! Write the equation of a line that includes the point (-4, 0) and has a slope of -3/5 in slope-intercept form. A) y = -3/5x - 12/5 B) y = -3/5x - 12 C) y = -3/5x - 5 D) y = -3/5x + 12/5
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okay what you think
I don't know that's why I need help...
okay
Well the equation is y-y1=m(x-x1). -4 is your X1, and 0 is your Y1. plug them in. And plug -3/4 into M.
y-y1=m(x-x1)
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-3/5 MY BAD.
as @ MarrBear said y-0=-3/5(x-(-4))
So it would be y=-3/5(x+4). Then Distribute.
y=-3/5x-(-3/5*-4)
What ^ No. LOL
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it is the same........ (x-(-4))=(x+4)
y=-3/5x-12/5
So Y = -3/5x - 12/5 is the correct answer?
yes
Thank you so much. If I click "best response" will take give you a medal?
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