Question

Will give medal.

Answer 1

@geerky42

Answer 2

Can you write \(\sqrt[5]{8}\) in the form \(8^{Some\;Fraction}\)?

Answer 3

like\[8\frac{ 1 }{ 5 }\] ?

Answer 4

Keep working on the super-script, but yes.

Okay, how about \(\sqrt{8}\)?

Answer 5

\[8\frac{ 1 }{ 2 }\]

Answer 6

the fractions should be exponents sorry...

Answer 7

No worries. Do the last one. \(\sqrt[3]{8^{5}}\)

Answer 8

\[8^{\frac{ 5 }{ 3 }}\]

Answer 9

@Jhannybean

Answer 10

I know how to turn them into fractions, I need help after that. I always seem to mess up that bit.

Answer 11

so when I multiply the top numbers do I multiply the 8's as well or just the fractions?

Answer 12

Finish up: \(8^{1/5 + 1/2 - 5/3}\)

Just add the fractions.

Answer 13

ahhh

Answer 14

wait there's a subtraction sign in there. Do I add them all or just 1/5 and ½ ?

Answer 15

Gotta find the LCD first.

Answer 16

Numerator: 1/5 + 1/2
Denominator - 5/3

Answer 17

I got \[-\frac{ 29 }{ 30 }\] is that right?

Answer 18

Yep

Answer 19

thank you both so much!

Answer 20

\(8^{-29/30} = \dfrac{1}{8^{29/30}} = \dfrac{1}{\sqrt[30]{8^{29}}} = \dfrac{1}{\sqrt[30]{2^{87}}} = \dfrac{1}{\sqrt[10]{2^{29}}}\)

Seriously, learn how to manipulate fluently. This will be important.

Answer 21

On a side note: \( \sqrt[m]{x^n} = x^{m/n}\) where x is any whole number integer.

Answer 22

Or doesn't necessarily have to be a whole number.

Answer 23

I wrote that backwards.

Answer 24

You DO have to be careful with even integers.

In the absence of other information \(\sqrt{x^{2}} = |x|\) NOT just 'x'. It's important.

Answer 25

Side note: \(\sqrt[m]{x^n} = x^{n/m}\) Is what I meant to write.