@geerky42
If f'(a) = 0, we can say that is relative extrema at f(x) at x=a, right?
yes
@geerky42
@phi
what is the question? You do know to find a min or max of f(x) you would find df/dx and set equal to 0. I would look at the graph for f'(x) and look for when it's zero also, the points on f'(x) where its slope is zero are where f''(0)=0. These are inflection points.
the question is in the creenshot
Yes, I see the question. But what do you not understand so that you can answer it ?
how do i figure out if the relative exterma is 1 or 0
relative extrema is another way to say local minimum or local max. In calculus they drum it into your head (hopefully!) that a max (for example) is where the slope of the tangent line is zero, i.e. where f'(x) is 0 Look at your graph. Do you see any places where the graph crosses the x-axis (i.e. its y value is 0, meaning f'(x) is zero)
yes
so that means it would be 1
It means statement I is true. There is an extrema at x=0 there is also a max/min at x=2, but they don't mention it. However, they do mention an inflection point. Did you learn how to identify an inflection point ?
uhh not that i remember lol could you explain?
The second derivative is zero
so this one does not have an inflation
inflection (inflation is something else) to find where the second derivative is zero, look for local min or max on the graph of the first derivative.
idk what youre trying to say..
im confused
im going with it has an inflection at 1
@ikram002p
@Loser66
@geerky42 @ganeshie8
I think this question is asking for *all* the statements that are true. Two of them are true.
agree with phi
go backward, forget about the graph. By definition, f has extrema at the points where f' =0, right? The graph is f' (not f) and to the graph, f' =0 at x =0 and x =1, so x =0 and x =1 are relative extrema. Period.
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