Question

A dentist's drill starts from rest. After 2.90 s of constant angular acceleration, it turns at a rate of 2.49 x 10^4 rev/min.
(a) Find the drill's angular acceleration.
rad/s2 (along the axis of rotation)

(b) Determine the angle through which the drill rotates during this period.

I have the answer I just don't know how to get it. Fan and Medal if you can explain the rotational motion equations

Answer 1

The angular acceleration is, by definition, the ratio between the variation of angular velocity and the time within that variation of angular velocity is occurred

Answer 2

the equation of motion is:
\[\frac{ d ^{2}\theta }{dt ^{2} }=\alpha \]
where \[\alpha \] is your angular acceleration