A dentist's drill starts from rest. After 2.90 s of constant angular acceleration, it turns at a rate of 2.49 x 10^4 rev/min.
(a) Find the drill's angular acceleration.
rad/s2 (along the axis of rotation)

(b) Determine the angle through which the drill rotates during this period.

I have the answer I just don't know how to get it. Fan and Medal if you can explain the rotational motion equations

Question

A dentist's drill starts from rest. After 2.90 s of constant angular acceleration, it turns at a rate of 2.49 x 10^4 rev/min. 
(a) Find the drill's angular acceleration.
  rad/s2 (along the axis of rotation)

(b) Determine the angle through which the drill rotates during this period.

I have the answer I just don't know how to get it. Fan and Medal if you can explain the rotational motion equations

michele_laino · Answer

The angular acceleration is, by definition, the ratio between the variation of angular velocity and the time within that variation of angular velocity is occurred

michele_laino · Answer

the equation of motion is:
$$\frac{ d ^{2}\theta }{dt ^{2} }=\alpha $$
where $$\alpha $$ is your angular acceleration