Question

Ok I have two questions. Can work one at a time.

One zero of f(x)=x^3+2x^2-5x-6 is 2. What are the other zeros of the function?
a.) 1 and 3
b.) -1 and -3
c.) 2 and -3
d.) 2 and 3

Which of the following quartic functions has x=-2 and x=-3 as its only two real zeros?
a.) x^4-5x^3+7x^2-5x+6
b.) x^4+5x^3+7x^2+5x+6
c.) x^4+5x^3+7x^2-5x-6
d.) x^4-5x^3+7x^+5x-6

Answer 1

The complete factor of f(x), is:
\[f(x)=(x-2)*(x+1)*(x+3)\]
so, you have other zeroes, try to write them, please

Answer 2

1 and 3

Answer 3

Sorry, incorrect answer!

Answer 4

please , you have to solve two linear equation, namely:
\[x+1=0,x+3=0\]

Answer 5

re-try, please!

Answer 6

x = -1 and x = -3

Answer 7

That's right!

Answer 8

Ok!, For your second answer, you have to substitute your number, namely -2 and -3 in all the equations indicated. When you get zero after both substitutions, you have found the right equation. Please try!