If m and k are positive and 10m^2k^-1 = 100m, what is m^-1 in terms of k? a. k/10 b. k/90 c. sqrt(k)/10 d. 1/10k e. 1/90k
\[10m ^{2}k ^{-1} = 100m\]
dividing both sides by \(m^2\) gives you \(m^{-1}\) on right hand side
if that doesn't look obvious, how about solving the equation for \(m\) ?
divide by 100?
yeah but there is m on both sides right ?
yea
maybe divide \(m^2\) both sides and see what u get
\[\large \rm 10m ^{2}k ^{-1} = 100m\] dividing \(\large \rm m^2\) both sides gives \[\large \rm \dfrac{10m ^{2}k ^{-1}}{m^2} = \dfrac{100m}{m^2}\]
ok yea i was trying to type that ^
next divide 100 both sides so that m will be isolated all by itself
why divide?
becaule you want to isolate m, and since 100 is attached to m, you want to get rid of it
dividing 100 both sides kills the 100 on right hand side
\[\large \rm 10k ^{-1} = \dfrac{100}{m}\] dividing 100 both sides you get \[\large \rm \dfrac{10k ^{-1}}{100} = \dfrac{1}{m}\]
\[\large \rm \dfrac{k ^{-1}}{10} = \dfrac{1}{m}\]
which is equal to 1/10k right
Yep ! notice the right hand side is same as \(\large \rm m^{-1}\)
alrighty, thank you a lot. it started making sense once you started working it out. i felt stupid for not realizing it before i posted it
Join our real-time social learning platform and learn together with your friends!