Question

Find the Maclaurin series for f(x) using the definition of a Maclaurin series. [Assume that f has a power series expansion. Do not show that
Rn(x) → 0.]

f(x) = 9(1 − x)^−2

Answer 1

whoa nelly
i hope that this is
\[f(x)=9^{1-x}-2\]

Answer 2

It's f(x) 9(1-x)^2 !

Answer 3

then all you need to do is expand

Answer 4

a polynomial is its own maclaurin series

Answer 5

As in just make it \[\sum_{n=0}^{\infty} 9/(1-n)^2\]

Answer 6

The idea is that if you have a polynomial, it's maclaurin series expansion is itself.
If f(x) = \(9(1-x)^{2}\), then the maclaurin series is \(9(1-x)^{2}\). Nothing changes.

Answer 7

But when I put that in as the answer, it tells me that it's the wrong answer.

Answer 8

wait, is it 9( 1-x)^-2 ?