WILL MEDAL AND FAN!!!!! PLEASE HELP! A snorkeler takes a syringe filled with 14mL of air from the surface, where the pressure is 1.0 atm, to an unknown depth. The volume of the air in the syringe at this depth is 8.5mL . a) What is the pressure at this depth? b) If the pressure increases by 1 atm for every additional 10 m of depth, how deep is the snorkeler? The answer to part a) is 1.6 atm. How do you solve part b) ?
@dumbcow
@cz1
please help
divide the rate by 10 ---> Increase of .1 atm for every 1 m in depth it increased by .65 atm so depth = 6.5
@dumbcow How did it increase by .65 atm
from 1 atm to 1.65 atm i see you rounded it to 1.6
part a) PV=nRT so in this case, Boyle's law applies\[P \propto \frac 1V\]
x = .607
now add that to 1
x = 1.607
woops, let me do part a) again
for part b) we have a linear relationship.... so, (change in depth) / ( change in pressure) is constant
PV = nRT , PV = k, since n, R, and T are constant in the problem (we can assume that) so we have P1 *V1 = k P2 *V2 = k substitute P1 * V1 = P2 * V2
For part a), I converted mL to L, and got 1.647atm. I'm still stuck with part b)
you dont need to
(1 atm)*(14 mL) = (x atm) * (8.5 mL) , since the units cancel
yes i got 1.647 as well
its a good idea though to change to Liters , in general
ok, thanks. could you please explain how to do part b
Change in Depth varies directly as change in Pressure
you can make an equation we have P = 1 atm , Depth = 0 P = 2 atm , Depth = 10 meters
@koook the change in pressure is .647 right for every .1 the depth goes down 1 meter thus depth = 6.47 m
Depth = 10*P -10
now plug in pressure from part a)
Depth = 10(1.647) - 10
THANK YOU SO MUCH @perl and @dumbcow and @PaxPolaris
:)
good job everyone
case closed :)
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