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Mathematics 15 Online
OpenStudy (anonymous):

All the following would be evidence that you do not have a normal distribution, except: the presence of multiple modes. the fact that 75% of the observations have a value below the mean. a normal quantile plot suggests an obviously curved line. the likelihood for all values of x is the same. None of the above I believe the correct answer is A, since a normal distribution does not have more than one mode according ot its definition.

OpenStudy (anonymous):

@perl

ganeshie8 (ganeshie8):

having multiple modes is a clear evidence that the distribution is not normal right ? so that cannot be your answer, strike it off

OpenStudy (anonymous):

oh i see i misread the question

ganeshie8 (ganeshie8):

yes its a tricky one, go thru remaining options and see if u can eliminate a few more

OpenStudy (anonymous):

Well since the normal curve has a theoretical area of 1 all the time, then if it were to come down to chance in any part of the area under the curve, the answer most suitable to not indicate it is not a normal distribution would have to be D

OpenStudy (anonymous):

haha lol, hbu @ganeshie8

ganeshie8 (ganeshie8):

let me give u a quick example : suppose u have a normal distribution of ages of "all the living people " are the numbers "20 years" and "200 years" equally likely ?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

Actually, that's not right, it's just worded weirdly so lets cross that out as well.

ganeshie8 (ganeshie8):

how many living people you know are 200 years old ?

OpenStudy (perl):

All the following would be evidence that you do *not* have a normal distribution,

OpenStudy (anonymous):

Perl gave away the answer xD

OpenStudy (perl):

no i didn't

OpenStudy (perl):

i just emphasized a part of the question

OpenStudy (anonymous):

that was the one i chose dude lol

OpenStudy (perl):

technically the probably of any x value is zero, because it is a continuous distribution

OpenStudy (anonymous):

byt ok ty guys for helping me learn how to read a question lol

OpenStudy (anonymous):

There we go perl

OpenStudy (perl):

P(X = x) = 0 , for any x

ganeshie8 (ganeshie8):

what do we have ztables for

OpenStudy (perl):

for intervals

OpenStudy (perl):

P ( a < X < b )

OpenStudy (perl):

P ( X > a) , P ( X < b ) , etc

OpenStudy (perl):

you would be right if it was a discrete distribution, P( x = 20) is different than P( x = 200 )

OpenStudy (anonymous):

So the answer is D?

OpenStudy (perl):

can't give out answer

ganeshie8 (ganeshie8):

so if the SAT scores are normaly distributed, the probability of getting a score of exactly 350 is 0 ?

OpenStudy (perl):

correct

OpenStudy (perl):

if you are using a continuous scale

OpenStudy (anonymous):

There's a probability that x is equal to a value of 0

OpenStudy (perl):

a better example is weight or temperature , continuous variables

ganeshie8 (ganeshie8):

yeah you're right, probability of getting a score of 350 or higeher is P(X > 350)

OpenStudy (perl):

this has to do with the way we define probability, as area under the curve

ganeshie8 (ganeshie8):

Right.

OpenStudy (perl):

P( X = a ) = integral { a, a} f(x) , but the area is zero

OpenStudy (perl):

P ( a < X < b ) = integral { a,b} f(x) , which is not zero if a =/= b

OpenStudy (anonymous):

It's just the way it's defined a better way would be to say specific value is 0

OpenStudy (perl):

this is for f(x) 'density' curve

OpenStudy (perl):

iam, you mean a better way to say it? any specific value is zero

OpenStudy (anonymous):

That's right

OpenStudy (anonymous):

I think its none of the above

OpenStudy (perl):

here is a classic example. suppose you have to pick a decimal randomly between [0,1]

ganeshie8 (ganeshie8):

that gives uniform distribution right

OpenStudy (perl):

right

OpenStudy (perl):

the probability of picking .348 , for example, is zero

OpenStudy (anonymous):

How do I give a thumbs up emoticon on here?

OpenStudy (perl):

the probability of picking a number between 0 and .5 is going to be 1/2

OpenStudy (anonymous):

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