Find the slope of a line that has an x-intercept of -2 and a y-intercept of 6.
can anyone help me?
anyone.......please i dont understand this question :(
hi....
hi...finally
:) so for finding a slope we need 2 points
do you knoiw these points?
no, it didnt give me a graph
Is there any other info we could sue?
the line intercept with x at -2 which means ?
at x=-2 y =0; so this is your first point
second point is y=6 when x=0
oh..so it would be (-2,0) and (6,0)?
sorry i meant (0,6)
\[m=\frac{ (y1-y2) }{ (x1-x2) }\]
yes
The standard Equation: \(y=mx+b\) We know that the \(y-intercept\) is equal to \(b\), so: \(y=mx+6\) We also know one point, the x-intercept. This is equal to \(-2,0\). Sub that into the equation: \(0=m*-2+6\) \(0=-2m+6\) Solve for the equation: \(0=-2m+6\) \(-6=-2m\) \(m=\frac{-6}{-2}\) \(m=3\)
so which formula am i supposed to use....AJ01 or ahsome?
Which ever makes sense for you @Addicto_
so their both right?
The equation: \[m=\frac{y_1-y_2}{x_1-x_2}\] Is more versatile. What I did worked for this question
And yes, they both give the same answer
ok thanks alot
No problem @Addicto_ :)
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