1. John Doe gets to go to the race track for a day. The track he is driving on is a perfect circle 750m in radius. If he is driving at 30m/s around the track, what is the centripetal acceleration experienced by the car, and what is the rotational velocity of the car?
2. Josh Beckett starts throwing his pitch; we assume that his arm moves in a perfect circular arc, and his arm is 0.7 m long. If he needs to release the ball with a tangential velocity of 35m/s what centripetal acceleration is required to achieve this?

Question

1. John Doe gets to go to the race track for a day. The track he is driving on is a perfect circle 750m in radius. If he is driving at 30m/s around the track, what is the centripetal acceleration experienced by the car, and what is the rotational velocity of the car?
2. Josh Beckett starts throwing his pitch; we assume that his arm moves in a perfect circular arc, and his arm is 0.7 m long. If he needs to release the ball with a tangential velocity of 35m/s what centripetal acceleration is required to achieve this?

surry99 · Answer

What is the formula for centripetal acceleration?

anonymous · Answer

http://www.clarkson.edu/highschool/k12/project/documents/Lesson5%20-%20%20Rotational%20Kinematics.pdf

surry99 · Answer

ok...so what is the formula for centripetal acceleration?
Hint: It depends on both r an v

anonymous · Answer

ma = m vt^2/r

surry99 · Answer

so cancel the m's and what do you have?

anonymous · Answer

a= vt^2/r

surry99 · Answer

yes, that is correct and can be used to solve these problems.

anonymous · Answer

How?

surry99 · Answer

look at the first question...r= 750 m and v(tangentail) = 30 m/s
therefore
acceleration = v(tangential)^2/r = (30 m/s)^2/750m

anonymous · Answer

Oh. So the answer is 1.2 m/s^2?

surry99 · Answer

yes....great!

anonymous · Answer

How about the rotational velocity?

anonymous · Answer

use velocity  = rotational velocity * radius