A baseball is popped straight up into the air and has has a hang time of 6.25s. Determine the height to which the ball rises before it reaches it's peak

Question

zpupster · Answer

half time going up and half time coming down
so
6.25/2=3.125s

from motion formula
change in distance(d) = -1/2at^2 - vFinalT
well vFinalt will = 0  going from + to - at the peak
and a is gravity which is -9.8m/s^2 or 32.2ft/s^2

lets plug the values in
d= -1/2at^2
d=(-1/2)(-9.8m/s^2)(3.125s)^2=?