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what is the quickest way to find \( \large remainder\) of \(\large\tt \begin{align} \color{black}{\dfrac{16^3+17^3-18^3+19^3}{70} }\end{align}\)
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you can mod 70 it
can u elaborate m not too familiar with mod
but this may not be the quickest way
mod is an operation
are you familar with % in c++
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remainder
yes
Have you covered modular arithmetic yet? If you haven't I don't think we should be doing this with mod, but if you have then you can break the expression into 4 parts and mod each of them. I'll do 16^3mod(70) as an example: 16^3mod(70) ≡ 16*16^2mod(70) ≡ 16*46mod(70) ≡ 36 The other 3 are just as easy. When you have the four parts you can add and subtract them as the original expression says then take mod(70) of that sum.
oh ok thnx
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