Question

I need help integrating x/x^2y+4y

Answer 1

With respect to what?

Answer 2

dx

Answer 3

Set \(u=y(x^2+4)\), then \(du=2xy~dx\), i.e. \(\dfrac{1}{2y}~du=x~dx\).
\[\int\frac{x}{y(x^2+4)}~dx=\frac{1}{2y}\int\frac{du}{u}\]